a^2+69a-4614=0

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Solution for a^2+69a-4614=0 equation:



a^2+69a-4614=0
a = 1; b = 69; c = -4614;
Δ = b2-4ac
Δ = 692-4·1·(-4614)
Δ = 23217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(69)-\sqrt{23217}}{2*1}=\frac{-69-\sqrt{23217}}{2} $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(69)+\sqrt{23217}}{2*1}=\frac{-69+\sqrt{23217}}{2} $

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